Question

the escape velocity for the earth is Vc. The escape velocity for a planet whose radius is four times and density is nine times that of the earth, is .
(a) 6Ve
(b) 12Ve
(c) 20Ve
(d) 36Ve
​steps pls..

Answer 1

SOLUTION.

4 × Radius of earth (R) = Radius of planet (r)...1

9 × Density of earth = Density of planet

9 × 3M/4πR³ = 3m/4πr³

9 × M/R³ = m/(4R)³

m = 64×9M

where m is the mass of planet

M is the mass of earth

R is the radius of earth

r is the radius of planet

m = 9×64M

we know that escape velocity = √GM/R

G is gravitation constant

M mass of planet

R Radius of planet

For earth = √GM/R

For planet = √Gm/r = 3×8√GM/4R

Escape velocity of planet = 12 (V)

where v is the escape velocity of earth.

option B

#answerwithquality

#BAL

Answer 2

Answer:

option B is the correct answer i hope

hope the before answer will help u...mark him as brinlist