Physics, asked by himanshukumar5689, 10 months ago

The escape velocity from the earth's surface is 11 km/s. The escape velocity from a planet having twice the radius and same mean density as that of earth is (a) 5.5 km/s (b) 11 km/s (c) 22 km/s (d) None of these

Answers

Answered by Anonymous

3

Answer:

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$\huge\blue{11km/s}$

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Answered by kalaiselvikalaiselvi

0

Answer:

option b

11km/s

hope this helps you

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