Question

The escape velocity of a satellite is 11.2 km/s if the satellite is launched at an angle of 60 degree with the vertical what will be the escape velocity

Answer 1

Answer:

it will be same

Explanation:

Bec escape velocity does not depend on angle

Answer 2

The escape velocity will be 11 km/s.

Explanation:

It is given that,

Speed of the body when it is projected upwards, v = 11 km/s

Angle of projection is of 45 degrees

The escape velocity of a projectile is given by the below formula as :

$v=\sqrt{\dfrac{2GM}{R}}$

Where

G is the universal gravitational constant

M is the mass of earth

R is the radius of earth

It is clear that the escape velocity is independent of the velocity of projection. So, if the body is projected at an angle of 45 degrees with the vertical, the escape velocity will be 11 km/s. Hence, this is the required solution.

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