Physics, asked by sujitpra10, 9 months ago

the escape velocity of an object from planet where g is 9 times that on the earth and whose radius is 4 times that of the earth in km/s is​

Answers

Answered by safnahakkim
1

Answer:escape velocity of planet=(2 *9 ge*4 Re)^1/2

              escape velocity of earth=(2* ge*Re)^1/2

Explanation:by dividing both equation ,we get

          escape velocity of planet=6 times escape velocity of earth

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