Question

The escape velocity of an object from the surface of planet P is 20 km\ s
The escape velocity of the object in C.G.S system of units is​

Answer 1

Answer:

Explanation:

20km/s = 20000m/s

             = 2000000 cm/s

Thus, 20 km/s in CGS is 2000000 cm/s

Answer 2

Escape velocity refers to the minimum velocity which is needed to leave a planet or moon. For instance, for any rocket or some other object to leave a planet, it has to overcome the pull of gravity.

The formula for escape velocity comprises of a constant, G, which we refer to as the universal gravitational constant. The value of it is = 6.673 × 10-11 N . m2 / kg2. The unit for escape velocity is meters per second (m/s).

Escape velocity = √2(gravitational constant (mass of the.planet of moon)radius of the planet or moon escape = √2GMR

Over here:

escape refers to the escape velocity (m/s)

G is the universal gravitational constant (6.673 × 10-11 N . m2 / kg2)

M refers to the mass of the planet or moon (kg)

R is the radius of the planet or moon (m)

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