Question

The escape velocity on the surface of earth is
11.2 km/s. What would be the escape velocity on
the surface of another planet of the same mass
but 1/4 times the radius of the earth?
(a) 22.4 km/s (b) 44.8 km/s
(c) 5.6 km/s (d) 11.2 km/s

Answer 1

Answer;At a certain velocity of projection the body will go out of the gravitational field of the earth and will never return to the earth, this velocity is known as escape velocity.

v e=$\sqrt{2GMe/Re}$

Thus escape velocity will get doubled.

so 11.2*2=22.4 km/s

Answer 2

Answer:

22.4

Explanation:

when we'll take square root of 1/4 then we will obtain 1/2 , then by moving 2 to the other side (left hand side) we will multiply it with 11.2 ms^-1 the answer will be 22.4 ms^-1