The excess pressure inside air bubble of water is
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Explanation:
it is found that the excess of pressure in a liquid drop it air bubble in a liquid is two times the surface tension of the liquid over the radius of a drop of the bubble . where as in case of soap bubble that excess of pressure is equal to fit times the surface tension over the radius.
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The excess pressure inside an air bubble of water is given by the formula
ΔP = 2S / R
where : ΔP = Excess pressure inside the air bubble
S = Surface tension of the liquid
R = Radius of the air bubble formed
- This excess pressure is due to the difference of pressure inside and outside the surface of the bubble
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