Physics, asked by udayyadav4918, 10 months ago

The excess pressure inside an air bubble released in mercury is

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Answered by Anonymous

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The excess pressure inside an air bubble released in mercury is Pez = 2S/R

According to excess pressure, if the air bubble is inside the mercury then, the excess pressure is the total amount of pressure that exceeds the outer side pressure of mercury.

Since, here we will have one free surface, thus - Pez = 2S/r, where S is the surface tension of the mercury and R is the radius of the air bubble

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