the exponential form of log root of x^4=8 is
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Answer:
We have,
log_{a}( { \sqrt{x} }^{4} ) = ylog
a
(
x
4
)=y
Since we write,
\begin{gathered} log_{2}(8) = 3 \\ \end{gathered}
log
2
(8)=3
as,
{2}^{3} = 82
3
=8
Hence, the exponential form will be,
{a}^{y} = ({ \sqrt{x}) }^{4}a
y
=(
x
)
4
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