Question

the expression 6 x 3+ax 2-(a+1)x+b has a remainder of 15 when divided by x+2 and. remainder of 24 when divided by x+1 show that a=8 and find the value of b

Answer 1

Answer:

Step-by-step explanation:

First you have to divide $6x^{3}+ax^{2} -(a+1)x+b$ divide this equation by x+2 and x+1

By diving the x+2 we get reminder 26+b which is equal to 15 as per question

26+b=15;

b=15-26

b=-11

and by dividing the that equation by x+1, we get reminder 2a+b-5 which is equal 24;

that is 2a+b-5=24;

putting a=8;

b=24+5-16=13