Question

* The expression of time period of angular SHM is...
2π
(a) TAngular velocity per unit angular displacement
2л
(6)
Angular acceleration per unit angular displacement
(c)
Angular velocity per unit angular displacement
211
(d)
Angular acceleration
per unit angular displacement
2π​

Answer 1

Expression for Time period of SHM:

• General expression for time period in SHM is 2π√(m/k).

• |F| = kx (definition of SHM )

$\sf T = 2\pi \sqrt{ \dfrac{m}{k} }$

$\sf \implies T = 2\pi \sqrt{ \dfrac{m}{( \dfrac{F}{x}) } }$

$\sf \implies T = 2\pi \sqrt{ \dfrac{m}{( \dfrac{m \times a}{x}) } }$

$\sf \implies T = 2\pi \sqrt{ \dfrac{x}{a} }$

Hope It Helps.