Question

The exterior angle < ACD of ∆ ABC is 110 ° and < A and < B are in the ratio 7 : 4 . find all the angles of∆ ABC .​

Answer 1

Answer:

The angle A = 70° and angle B = 40°.

Step-by-step explanation:

Since we have given that

Ratio of angles of A and B are 7:4.

So, the angle A be 7x

angle B be 4x.

Measure of exterior angle ACD = 110°

According to question, we get that

\begin{gathered}\angle A+\angle B=110^\circ\\\\7x+4x=110^\circ\\\\11x=110^\circ\\\\x=\dfrac{110}{11}\\\\x=10^\circ\end{gathered}

∠A+∠B=110

∘

7x+4x=110

∘

11x=110

∘

x=

11

110

x=10

∘

Hence, the angle A = 70° and angle B = 40°.

# learn more:

Angle ABD and angle ACE is exterior angle of ∆ABC. if angle ABD=110° and angle ACE=150°, then find angle A.

Answer 2

Step-by-step explanation:

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