Question

the exterior angle of a polygon are 2x5°,3x+15,4x,5x,x+10​

Answer 1

Answer:

We know that Sum of all angles of a hexagon=720

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⇒2x+5+3x−5+x+40+2x+20+2x+35=720

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⇒10x+95

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=720

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⇒10x=720

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−95

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=625

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∴x=

10

625

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=62.5

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Hence the angles are:

2x+5=2×62.5+5=130

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3x−5=3×62.5−5=182.5

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x+40=62.5+40=102.5

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2x+20=2×62.5+20=145

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2x+35=2×62.5+35=160‬

∘

Answer 2

Step-by-step explanation:

The sum of angles of a hexagon is 720⁰.

$2x+5+3x+15+4x+5x+x+10 \\ 15x + 30 = 720 \\ 15x = 720 - 30 = 690 \\ 15x = 690 \\ x = \frac{690}{15} = 46ans$

So the angles will be::

Angle 1:: 97⁰

Angle 2:: 153⁰

Angle 3:: 184⁰

Angle 4:: 230⁰

Angle 5:: 56⁰