the exterior angle of a regular polygon is one third of its interior angle find the number of sides in the polygon
Answers
Answered by
7
Given that exterior angle of a regular polygon is 1/3rd of its interior angle.
We know that measure of an interior angle = (n-2)(180/n) and the measure of an exterior angle = (360/n).
1/3 = (360/n) / (n-2)(180/n)
1/3 = (360/n) / n/(n - 2) * 180
1/3 = (360/n) / n(180n - 360)
1/3 = (360)/(180(n-2))
1/3 = 2/(n-2)
1(n - 2) = 3 * 2
n - 2 = 6
n = 2 + 6
n = 8.
Therefore the number of sides in the polygon = 8.
Hope this helps!
We know that measure of an interior angle = (n-2)(180/n) and the measure of an exterior angle = (360/n).
1/3 = (360/n) / (n-2)(180/n)
1/3 = (360/n) / n/(n - 2) * 180
1/3 = (360/n) / n(180n - 360)
1/3 = (360)/(180(n-2))
1/3 = 2/(n-2)
1(n - 2) = 3 * 2
n - 2 = 6
n = 2 + 6
n = 8.
Therefore the number of sides in the polygon = 8.
Hope this helps!
Similar questions