the exterior angle of a regular polygon is two fifth of its interior angle how many sides has the polygon
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The exterior angle of a regular polygon is one-third of its interior angle. How many sides does the polygon have? Np. of sides ofregular polygon = 360/45 = 8. The figure is a regular octagon and it has 8 equal sides, 8 vertices, and 20 diagonals.
kishankumar81:
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Hello! ! !
Hey my dear friend here is your answer _________________
Let the interior angle be x
exterior angle will be (180- x )
(180 - x ) = 1x/5
900-5x = x
900= x + 5x
900= 6x
x = 900/6
x= 150
each interior angle is 150°
the number of sides are
{ n - 2 ) * 180} /n = 150
( n - 2 ) * 180 = 150n
n-2 = 150n / 180
n-2 = 5n/6
6(n - 2)= 5n
6n - 5n = 12
n = 12
number of sides= 12
__________________________
HOPE THIS ANSWER WILL HELP U dear....
@Neha...
Hey my dear friend here is your answer _________________
Let the interior angle be x
exterior angle will be (180- x )
(180 - x ) = 1x/5
900-5x = x
900= x + 5x
900= 6x
x = 900/6
x= 150
each interior angle is 150°
the number of sides are
{ n - 2 ) * 180} /n = 150
( n - 2 ) * 180 = 150n
n-2 = 150n / 180
n-2 = 5n/6
6(n - 2)= 5n
6n - 5n = 12
n = 12
number of sides= 12
__________________________
HOPE THIS ANSWER WILL HELP U dear....
@Neha...
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