the exterior angle of a triangle is (2x+10)°,(3x-5)° and (2x+40)° calculate x, the smallest interior angle and the largest interior angle
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hey mate your answer↓
the sum of measure of exterior angles of triangle is 360°
(2x+10) +(3x-5) +(2x+40)=360
2x+3x+2x+10-5+40=360
7x+45=360
7x=360-45
x=315/7
x=45
2x+10=2×45+10=90+10=100
3x-5=3×45-5=135-5=130
2x+40=2×45+40=90+40=130
hope that it will help you
the sum of measure of exterior angles of triangle is 360°
(2x+10) +(3x-5) +(2x+40)=360
2x+3x+2x+10-5+40=360
7x+45=360
7x=360-45
x=315/7
x=45
2x+10=2×45+10=90+10=100
3x-5=3×45-5=135-5=130
2x+40=2×45+40=90+40=130
hope that it will help you
connectsalman:
thanks mate but its part a...
i want answer of part b and c also
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