Question

the sum of interior angles of a polygon is twice the sum of its exterior angles find the number of sides of the polygon

Answer 1

Answer:

Step-by-step explanation:

The sum of the interiorof a regular polygon=(2n-4)×90° (where n= number of sides)

Sum of exterior angle of a regular polygon=360°

According to question

(2n-4)×90°=2×360°

2n-4 =(2×360°)/ 90°

2n-4= 2×4

2n-4=8

2n=8+4

2n=12

n=12/2=6

Answer 2

The sum of the interior of a regular polygon=(2n-4)×90° (where n= number of sides)

Sum of exterior angle of a regular polygon=360°

According to question

(2n-4)×90°=2×360°

2n-4 =(2×360°)/ 90°

2n-4= 2×4

2n-4=8

2n=8+4

2n=12

n=12/2=6