Two trains A and B start simultaneously in the opposite direction from two points A and B and arrive their destination 9 and 4 hours after their meeting each other. At what rate does the second train B travel if the first train travels at 80 km per hour.
Answers
Answered by
9
Answer:
If the trains meet T hours after leaving, then
distance left to be covered by A = distance covered by B in T hours
and
distance left to be covered by B = distance covered by A in T hours.
So if the speed of train B is b kmph, then we have:
120*16 = bT and 9b = 120T
Substitute T from the second eqn into the first and you have:
9b^2/120 = 120*16
=> b = 120* 4/3 = 160 kmph
Step-by-step explanation:
Similar questions