the exterior angle of a triangle is 70 and the interior opposote angles are in the ratio 3:4 . find all the three angles of the triangle
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Answered by
43
let the opposite angles be 3x and 4x
then
exterior angle = sum of opposite interior angles
implies
70 = 3x + 4x
⇒7x = 70
⇒x=70÷7
⇒x=10
so opposite angles are
3x = 3×10 = 30
4x = 4×10 = 40
now
third angle = ?
we know that
the sum of all angles of a triangle are 180
⇒30 + 40 + third angle = 180
⇒70 + third angle = 180
⇒third angle = 180 - 70
= 110
so the three angles are
first angle = 30
second angle = 40
third angle = 110
hope it helps
please mark brainliest
then
exterior angle = sum of opposite interior angles
implies
70 = 3x + 4x
⇒7x = 70
⇒x=70÷7
⇒x=10
so opposite angles are
3x = 3×10 = 30
4x = 4×10 = 40
now
third angle = ?
we know that
the sum of all angles of a triangle are 180
⇒30 + 40 + third angle = 180
⇒70 + third angle = 180
⇒third angle = 180 - 70
= 110
so the three angles are
first angle = 30
second angle = 40
third angle = 110
hope it helps
please mark brainliest
Answered by
19
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then
As per the Highschool exterior angle theoremexterior angle = sum of opposite interior angles
implies
70 = 3x + 4x
⇒7x = 70
⇒x=70÷7
⇒x=10
so opposite angles are
3x = 3×10 = 30
4x = 4×10 = 40
now
third angle = ?
we know that
the sum of all angles of a triangle are 180
⇒30 + 40 + third angle = 180
⇒70 + third angle = 180
⇒third angle = 180 - 70
= 110
so the three angles are
first angle = 30
second angle = 40
third angle = 110
hope it helps
please mark brainliest