Question

. The exterior angles of a pentagon are 2x°,(2x+5)°,(3x+10)°,(3x-15)°, and (x+30 )°
a. Find the value of x
b. Find the smallest interior angle of the pentagon
c. Find the largest interior angle of the pentagon

Answer 1

Step-by-step explanation:

sum of angles is360

then 2x+5+3x+10+3x-15+2x+X+30 =360

15 -15 get cancel

11x=330

x=30

weget xas 30

then the smallest angle is 2x; X+30 =60

and largest angle is 3x+10 = 100

this is the answer for above question

Answer 2

Answer:

exterior angle of any polygon=360°

so,(2x+5)°+(3x+10)°+(3x-15)°+(x+30)°=360°

(9x+30)°=360°

9x=(360-30)°

x=330/9

x=36.37