Question

The exterior angles of a quadrilateral are y°, (2y+5)°,(y+15)° and (3y-10)°, find y°

Answer 1

Answer:

50

Step-by-step explanation:

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Answer 2

Answer:

As we know that sum of all the angles of a quadrilateral is 360°

so,

=> y°+(2y+5)°+(y+15)°+(3y-10)°=360°

=> y+2y+5+y+15+3y-10=360

=> y+2y+y+3y+5+15-10=360

=> 7y+10=360

=> 7y=360-10

=> 7y=350

=> y=350/7

=> y=50

therefore,y=50°

Hope it helps u