Question

the exterior angles of heptagon are y, 2y , 3y , 4y , 5y , and 6y . find the value of y​

Answer 1

Given exterior angles of heptagon are: $y,2y,3y,4y,5y,6y.$

We know that the number of vertices each vertex can combine is $6.$

Therefore:

$y+2y+3y+4y+5y+6y=6(90)$

$y+2y+3y+4y+5y+6y=540$

$21y=540$

$y=\frac{540}{21}$

$y=\frac{180}{7} .$