the external dimensions of a closed wooden box are 25cm×23cm×18cm. If the thickness of the wood used is 2cm,find the total inner surface of the box
Answers
Answer:Let we consider them as two different cuboids.
So dimensions of first cuboids are
(25*23*18)cm^3
Difference in dimensions is of (2*2)cm because thickness is of 2cm.
So dimensions of second cuboid are
(21*19*14)cm^3
Total inner surface of the box is
2(lb+bh+lh)
2(21*19+19*14+21*14)
2(399+266+294)
(2*959)cm^2
Ans...1918cm^2
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Answer:
Let we consider them as two different cuboids.
So dimensions of first cuboids are
(25*23*18)cm^3
Difference in dimensions is of (2*2)cm because thickness is of 2cm.
So dimensions of second cuboid are
(21*19*14)cm^3
Total inner surface of the box is
2(lb+bh+lh)
2(21*19+19*14+21*14)
2(399+266+294)
(2*959)cm^2
Ans...1918cm^2
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