Math, asked by lalankumarzpbgs, 10 months ago

the external dimensions of a closed wooden box are 25cm×23cm×18cm. If the thickness of the wood used is 2cm,find the total inner surface of the box​

Answers

Answered by adityamittal64
26

Answer:Let we consider them as two different cuboids.

So dimensions of first cuboids are

(25*23*18)cm^3

Difference in dimensions is of (2*2)cm because thickness is of 2cm.

So dimensions of second cuboid are

(21*19*14)cm^3

Total inner surface of the box is

2(lb+bh+lh)

2(21*19+19*14+21*14)

2(399+266+294)

(2*959)cm^2

Ans...1918cm^2

Hope it helps.......

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Answered by ItzBrainlyGirl024
11

Answer:

Let we consider them as two different cuboids.  

So dimensions of first cuboids are

(25*23*18)cm^3

Difference in dimensions is of (2*2)cm because thickness is of 2cm.

So dimensions of second cuboid are

(21*19*14)cm^3

Total inner surface of the box is

2(lb+bh+lh)

2(21*19+19*14+21*14)

2(399+266+294)

(2*959)cm^2

Ans...1918cm^2

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