Question

the external dimensions of a wooden box are 18 cm, 10 cm and 6 cm respectively and the thickness of wood is 5 mm. if the mass of empty box is 3.15 kg, find the mass of 1 cubic cm of wood.

Answer 1

external length=18cm
external breadth=10cm
external height=6cm
external volume=(18*10*6)cm³=1080cm³
thickness=5mm=0.5cm
internal length=(18-2*0.5)cm=17cm
internal breadth=(10-2*0.5)cm=9cm
internal height=(6-2*0.5)cm=5cm
internal volume=(17*9*5)cm³=765cm³
capacity=external volume/internal volume
=1080/765=1.411cm³

Answer 2

Answer:

10 g

Step-by-step explanation:

Let the external length,breadth and height of the

closed box be L , B and H are respectively. Let

the internal length,breadth and height of the

closed box be l , b and h are respectively.

Thickness = 5 mm = 0.5 cm

Then, L = 18 cm, B = 10 cm , H = 6 cm

l = (18 - 2 × 0.5) cm = 17 cm

b = (10 - 2 × 0.5) cm = 9 cm

and h = (6 - 2 × 0.5) cm = 5 cm

External volume of the box = L × B × H = 1080 cm³

Internal volume of the box = l × b × h = 765 cm³

Volume of the wood = External volume -

Internal volume

= (1080-765) cm³ = 315 cm³

Weight of the empty box = 3.15 kg

Weight of 315 cm³ of wood = 3.15 kg

Weight of 1 cm³ of wood = 3.15/315 kg

= 0.01 kg/cm³

Mass of 1 cm³ = 10 g

HOPE IT HELPS.....