Question

The external radius and the length of a hollow wooden log are 16 cm and 13 cm respectively. If its thickness is 4 cm then find its T.S.A.

Answer 1

TSA OF cylinder is = 2πrh+2πr2

HERE WE HAVE

h = height or length of cylinder.

r = radius of cylinder .

total surface area of cylinder in this case is :

outer area - inner area

inner radius of cylinder = outer radius - thickness

16 - 4 = 12.

we have =

2πR(R + H) - 2πr(r+h)

2π16(16+13) - 2π12(12+13)

2π(464 - 300)

2π(164)

= 1030.44cm^2

HOPE THIS WILL HELP PLEASE MARK AS BRAINLIEST AND FOLLOW ME.

Answer 2

Answer:

TSA OF cylinder is = 2πrh+2πr2

HERE WE HAVE

h = height or length of cylinder.

r = radius of cylinder .

total surface area of cylinder in this case is :

outer area - inner area

inner radius of cylinder = outer radius - thickness

16 - 4 = 12.

we have =

2πR(R + H) - 2πr(r+h)

2π16(16+13) - 2π12(12+13)

2π(464 - 300)

2π(164)

= 1030.44cm^2

HOPE THIS WILL HELP PLEASE MARK AS BRAINLIEST AND FOLLOW ME.

Step-by-step explanation: