The external radius and the length of a hollow wooden log are 16 cm and 13 cm respectively. If its thickness is 4 cm then find its T.S.A.
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Answered by
27
TSA OF cylinder is = 2πrh+2πr2
HERE WE HAVE
h = height or length of cylinder.
r = radius of cylinder .
total surface area of cylinder in this case is :
outer area - inner area
inner radius of cylinder = outer radius - thickness
16 - 4 = 12.
we have =
2πR(R + H) - 2πr(r+h)
2π16(16+13) - 2π12(12+13)
2π(464 - 300)
2π(164)
= 1030.44cm^2
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Answered by
5
h = height or length of cylinder.
r = radius of cylinder .
total surface area of cylinder in this case is :
outer area - inner area
inner radius of cylinder = outer radius - thickness
16 - 4 = 12.
we have =
2πR(R + H) - 2πr(r+h)
2π16(16+13) - 2π12(12+13)
2π(464 - 300)
2π(164)
= 1030.44cm^2
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