Question

The faces of a die bear numbers 0,1,2,3,4,5. If the die is rolled twice, then find the probability that the product of digits on the upper face is zero.

Answer 1

the probability is 2/12
                            1/6

Answer 2

Answer:

$\text{Probability}=\frac{1}{6}$

Step-by-step explanation:

Given : The faces of a die bear numbers 0,1,2,3,4,5. If the die is rolled twice,

To find : The probability that the product of digits on the upper face is zero.

Solution :

If dice is twice rolled, with numbers 0,1,2,3,4,5

Then the outcomes were,

         0              1             2         3         4               5

0    (0, 0)         (0,1)        (0,2)     (0,3)   (0,4)         (0,5)

1      (1,0)          (1, 1)   (1, 2)          (1, 3)        (1, 4)         (1, 5)        

2     (2,0)        (2, 1)          (2, 2) (2, 3) (2, 4) (2, 5)

3     (3,0)         (3, 1)          (3, 2) (3, 3) (3, 4) (3, 5)

4 (4,0)         (4, 1)        (4, 2) (4, 3) (4, 4) (4, 5)  

5 (5,0)         (5, 1)        (5, 2) (5, 3) (5, 4) (5, 5)

We have to find the probability that the product of digits on the upper face is zero.

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

Favorable outcome = 6 (1st row complete)

Total number of outcome = 36

Probability drawn is  

$\text{Probability}=\frac{6}{36}=\frac{1}{6}$