Question

the factor of p⁶ + p³ - p² + p - 1 is​

Answer 1

Answer: $Let p−1=0p=1For p−1 to be factor, the equation on substituting p=1 should equate to 0i) f(p)=p10−1f(1)=1−1=0ii) f(p)=p11−1f(1)=1−1=0∴ Hence p−1 is a factor of bothp10−1 & p11−1$

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