Question

the factorisation of a²(b+c)+b²(c+a)+c²(a+b)+2abc​

Answer 1

Answer:

This is a classic.

a^2(b - c) + b^2(c-a) + c^2(a - b)

= a^2b - a^2c + b^2c - b^2a + c^2a-c^2b

=a^2b - b^2a - a^2c + b^2c + c^2a -c^2b

= ab(a - b) - c(a^2 - b^2) +c^2(a - b)

=ab(a - b) -c(a - b)(a + b) +c^2(a - b)

=(a - b)(ab - c(a + b) +c^2)

=(a - b)(ab - cb -ca + c^2)

= (a - b)(b(a-c) -c(a-c))

=(a-b)(b-c)(a-c)

Step-by-step explanation:

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