36.
The mean and standard deviation of 20 observations are found
to be 10 and 2 respectively. On rechecking, it was found that an
observation 8 was incorrect. Calculate the correct mean and
standard deviation in each of the following cases:
() If wrong item is omitted.
(ii) If it is replaced by 12
Answers
Answer:
(i) Correct Mean = 10.105 , Correct Standard deviation = 1.998
(ii) Correct Mean = 10.2 , Correct Standard deviation = 1.9894
Step-by-step explanation:
We are given that the mean and standard deviation of 20 observations are found to be 10 and 2 respectively. And On rechecking, it was found that an observation 8 was incorrect.
(i) If wrong item is omitted ;
Mean formula is given by, =
Mean of 20 observations =
So, = 10 * 20 = 200.
Now if wrong item of 8 is omitted, then ;
Correct = 200 - 8 = 192 and number of observation is 20 - 1 = 19
So, Correct Mean = 192 ÷ 19 = 10.105
Now, Standard deviation formula, S.D. =
S.D. of 20 observations =
So, = = 2076
Now, if wrong item of 8 is omitted, then ;
Correct = 2076 - = 2012 and number of observation is 20 - 1 = 19
Therefore, Correct S.D. = = 1.998
(ii) If wrong item is replaced by 12;
Mean formula is given by, =
= 10 * 20 = 200.
Now if wrong item of 8 is replaced by 12, then ;
Correct = 200 - 8 + 12= 204 and number of observation is 20 - 1 +1 = 20
So, Correct Mean = 204÷ 20 = 10.2
Now, Standard deviation formula, S.D. =
= = 2076
Now if wrong item of 8 is replaced by 12, then ;
Correct = 2076 - + = 2156 and no. of observation is 20 - 1 + 1 = 20
Therefore, Correct S.D. = = 1.9894
Answer:
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