Math, asked by sivamthegreat3729, 3 months ago

The factorisation of (l + m)2 – 4lm is​

Answers

Answered by rishabhyadav2211
2

Answer:

Answer:(l-m)^2

Step-by-step explanation:

(l+m)^2-4lm

(l+m)^2-4lm ( l^2 + 2lm + m^2 ) -4lm

(l+m)^2-4lm ( l^2 + 2lm + m^2 ) -4lm l^2 - 2lm + m^2

(l+m)^2-4lm ( l^2 + 2lm + m^2 ) -4lm l^2 - 2lm + m^2 l^2-m^2

(l+m)^2-4lm ( l^2 + 2lm + m^2 ) -4lm l^2 - 2lm + m^2 l^2-m^2( l - m ) ( l - m)

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