the factorise the following
z^2+4z-12
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hope that u understood
z^2+4z-12
Step-by-step explanation:
first we have to find the factors of this eq. I.e 1×-12=-12
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6.× -2
then . use the 6 and -2
z^2+6z-2z-12=0
z(z+6)-2(z+6)=0
(z-2)(z+6)=0
z=2. z=-6
factors are 2 and -6
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