Math, asked by saritasinghsolanki80, 1 year ago

The factors of (1- 6z +9 z ^2)

Answers

Answered by Anonymous
11
Hii
Nice question

Question :-

Find the factors of 9z² - 6z + 1

Answer :-

= 9z² - 3z - 3z + 1

= 3z( 3z - 1 ) - 1( 3z - 1 )

= (3z - 1)(3z - 1)

Factors :- 1. 3z - 1
2. 3z - 1

Hope this helps.

saritasinghsolanki80: exceelent yrr
Answered by rr1321236
0

Answer:

It is [3z-1]²..........

Step-by-step explanation:

Hope this will help you

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