The factors of (1 - 6z + 9z2)
Answers
Answered by
23
Answer:
1-6z+9z^2
=1 - 2×1×3z + (3z)^2
=(1-3z)^2
Answered by
4
Answer:
Step-by-step explanation:
9z2-6z+1=0
9z2-3z-3z+1=0
3z(3z-1)-1(3z_1)=0
Z=1/3
Similar questions