Math, asked by NerdyGirly, 4 days ago

the factors of 3+23y-8y² are​

Answers

Answered by arinimaity2007
2

3+23y-8y^2

=-(8y^2-23y-3)

=-{8y^2-(24-1)y-3}

=-{8y^2-24y+y-3}

=-{8y(y-3)+1(y-3)}

=-{(y-3)+(8y+1)}

Answered by anuhya2007
0

Answer:

hi the answer is

-1 (y - 3) (8y + 1)

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