Math, asked by sha2007, 5 months ago

The factors of 4y²-12y+9 is ….​

Answers

Answered by bagkakali
1

Answer:

4y^2-12y+9

=(2y)^2-2.2y.3+(3)^2

=(2y-3)^2

factors of 4y^2-12y+9 are

(2y-3),(2y-3)

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