the factors of 8+x^3 are
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Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2) a 3 - b 3 = ( a - b ) ( a 2 + a b + b 2 ) where a=2 and b=x . Raise 2 to the power of 2 .
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factors of 8+x^3 are (x+2)(x^2-2x+4)
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