the factors of 8a^3+b^3-6ab+1
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8a³ + b³ + 1 - 6ab
= (2a)³ + (b)³ + 1³ - 3(2a)(b)(1)
= [2a + b + 1][(2a)²+ b² + 1² - (2a)b - (2a)1 - b(1)]
= [2a + b + 1][(4a²+ b² + 1 - 2ab - 2a - b]
identity used
= x³ + y³ + z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx)
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