Math, asked by annikasonale12267dch, 5 months ago

The Factors of p³+27/(8p³) is ​

Answers

Answered by vrkinage68
2

Answer:

(p + 1/p - 1/3)(p² + 1/p² - 8/9  +1/3p  + p/3)

Step-by-step explanation:

p^3+1/p^3+26/27 solve the factorization

p³ + 1/p³ + 26/27

= p³ + 1/p³ -1/27  + 1

= p³ + 1/p³ + (-1/3)³  - 3* p (1/p)(-1/3)

using identity

a³+ b³ + c³ - 3abc = (a + b + c) (a² + b² + c² - ab - bc - ca)

a = p  b = 1/p  c = -1/3

= (p + 1/p - 1/3)(p² + 1/p² + 1/9  - 1  +1/3p  + p/3)

= (p + 1/p - 1/3)(p² + 1/p² - 8/9  +1/3p  + p/3)

Answered by Aashon
2

Answer:

(p+1/p-1/3)(p²-8/9+1/3p+p/3)

Step-by-step explanation:

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