Question

The factors of the expression k2+4k-32are

Answer 1

Answer:

(k-4) (k+8)

Step-by-step explanation:

factor k2+4k−32.

To factor the quadratic function k2+4k−32,

we should solve the corresponding quadratic equation k2+4k−32=0.

Indeed, if k1 and k2 are the roots of the quadratic equation ak2+bk+c=0, then ak2+bk+c=a(k−k1)(k−k2).

Solve the quadratic equation k2+4k−32=0.

solve the quadratic equation k2+4k−32=0 by using quadratic formula.

(see in image also )

The standard quadratic equation has the form ak2+bk+c=0.

In our case, a=1, b=4, c=−32.

Now, find the discriminant using the formula D=b2−4ac: D=42−4⋅1⋅(−32)=144.

Find the roots of the equation using the formulas k1=−b−D−−√2a

and

k2=−b+D−−√2a

k1=−4−144−−−√2⋅1=−8

and

k2=−4+144−−−√2⋅1=4

Answer: k1=−8; k2=4

Therefore, k2+4k−32=(k−4)(k+8).

(k2+4k−32)=(k−4)(k+8)

Thus, k2+4k−32=(k−4)(k+8).

Answer:

Answer: k2+4k−32=(k−4)(k+8).