Math, asked by echinta1975, 9 months ago

The factors of x^2-4x-5 is/are ............................​

Answers

Answered by duggurao
1

Answer:

x^2-4x-5=0

x^2-5x+X+5=0

X(x-5)+1(x-5)=0

(x-5)(X+1)=0

(x-5)=0,(X+1)=0

so X=5,-1

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