Question

The factors of x^2 +4y^2 + 4y - 4xy – 2x - 8 are​

Answer 1

Answer:

To my knowledge

Step-by-step explanation:

x^2-4xy+4y^2-2x+4y-8

=(x-2y)^2 -2(x-2y) -8

=(x-2y)[(x-2y)-2] -8

=(x-2y)(x-2y-2)-8