Math, asked by heroboymithran, 6 months ago

The factors of x + 4y + 4y - 4xy - 2x - 8 are :
(1) (x-2y - 4)(x - 2y + 2)
(3) (x + 2y - 4)(x+2y + 2).
(2) (x – y + 2)(x - 4y - 4)
(4) None of these

Answers

Answered by Stuti1990
2

Answer:

Please mark as brainliest please mark as brainliest please

Attachments:
Answered by roshniisharmaa
2

Answer:

  1. (x−2y−4)(x−2y+2)

Step-by-step explanation:

The value of x2+4y2+4y−4xy−2x−8 is

=x2+4y2−4xy+4y−2x−8

=(x−2y)2+2(2y−x)−8

=(x−2y)2−2(x−2y)−8

Let A=x−2y

Thus A2−2A−8 

=(A−4)(A+2)

Re-substitute the value of A

Thus x2+4y2+4y−4xy−2x−8=(x−2y−4)(x−2y+2)

I HOPE IT HELPS TO YOU

PLZZ MARK MY ANSWER AS BRILLIANT

Similar questions