The far point of a myopic person is 80 cm in front of the eye .What is the nature and power of the lens required to correct the problem?
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u =infinity
v= -80 cm
1/v-1/u =1/f
1/infinity - 1/-80
0-1/-80 = 1/80
1/80 =1/f
f = 80cm
P=1/f = 1.25 m
P= 1.25 D
Concave lens is used to correct this defect and concave is a diveeging lens.
Itsmine:
thanks
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Explanation:
To correct the myopia the person concerned should use concave lens of focal length (f) = -80 cm = -0.80 m
Power of lens (P) = 1/f(m) = 1/-0.80 = 100/-80 = -1.25 D.
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