The far point of myopic person is 75 cm in front of the eye. The nature and power of the lens required to
correct the problem, will be ?
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Heya......!!!
It's Given that Far point of a myopic eye is 75 cm.
=> For a myopic person ,, We know that => Focal length, f = – far point
So ,,
f = - 75 cm
power, P = 1 / f ( m )
Power ( P ) = 100÷ -75 (( after changing 75 cm to m )).
P = - 1.33 D .
Hope it helps u ^_^
It's Given that Far point of a myopic eye is 75 cm.
=> For a myopic person ,, We know that => Focal length, f = – far point
So ,,
f = - 75 cm
power, P = 1 / f ( m )
Power ( P ) = 100÷ -75 (( after changing 75 cm to m )).
P = - 1.33 D .
Hope it helps u ^_^
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