Question

The fare if taxi is #15 for the first km and rises by #10 for each additional km. weather this situation involved in Arithmetic progression ? why?​

Answer 1

Answer:

This is in Ap

Step-by-step explanation:

Because the charge for the first km is 15rs and 10 Rs increases after that per km.

so now let's look at the AP

15 , 25 , 35 , 45 , 55.

now if you will subtract the 1st term from the second term you will get the difference as 10. now subtract the 2nd term from the 3rd term, you will get the difference as 10. so thus this is an AP

(i) 25-15 = 10

(ii) 35-25=10