Math, asked by vinodkumar842784, 8 months ago

the father's age is 6 Times his sons age for years hence the age of the father will b 4 time's his sons age the present ages in years of the son and the father are respectively​

Answers

Answered by arnav112005
1

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Answered by PixleyPanda
1

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20

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