Question

The father's age is seven times his son's Age.five years hence,the age of the father will be five times his son's age. form two linear equations for this situation​

Answer 1

Step-by-step explanation:

Let the father present age =x years and son present age =y years

According to the first condition

5 years later father will be (x+5) years old and son will be (y+5) years old.

⇒x+5=3(y+5)

⇒x+5=3y+15⇒x=3y+10•••••••••(1)

According to the second condition

5 years ago father was (x−5) years old and son was (y−5) years old.

⇒x−5=7(y−5)

⇒x−5=7y−35

⇒x−7y=−30•••••••••(2)

Put the value of x from (1)

⇒3y+10−7y=−30⇒−4y=−40⇒y=10

Put y=10 in eq1

⇒x=3×10+10=40

Hence, Father present age =40 years

Son present age =10 years