Question

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively

(A) 4 and 24                                       

(B) 5 and 30

(C) 6 and 36                                       

(D) 3 and 24​

Answer 1

Answer: (C)

Explanation: Let the age of father be x and of son is y.

Then according to question,

x = 6y …..(i)

Four years hence age of son will be y + 4 and age of father will be x + 4

Then according to question,

x + 4 = 4 (y + 4)

x – 4y = 12 …..(ii)

Solving equations (i) and (ii) we get:

y = 6 and x = 36

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Answer 2

Answer:

4 and 24

5 and 30

6 and 36

3 and 24

Answer :  C

Solution :

Let x yr be the present age of father and y yr be the present age of son.

Four years hence, it has relation by given condition,

(x+4)=4(y+4)

x−4y=12 and  x=6y

On putting the value of x from Eq. (ii) in Eq. (i), we get

6y−4y=12

2y=12

y=6

When y = 6, then x = 36

Hence, present age of father is 36 yr and age of son is 6 yr.