Question

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively

(A) 4 and 24                                       

(B) 5 and 30

(C) 6 and 36                                       

(D) 3 and 24​

Answer 1

Answer: (C)

Explanation: Let the age of father be x and of son is y.

Then according to question,

x = 6y …..(i)

Four years hence age of son will be y + 4 and age of father will be x + 4

Then according to question,

x + 4 = 4 (y + 4)

x – 4y = 12 …..(ii)

Solving equations (i) and (ii) we get:

y = 6 and x = 36

hope it's helps you ❤️

Answer 2

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▪️Let the present age of father's be x years and ▪️present age of son's be y years.

▪️According to the problem

▪️x=6y 

▪️After 4 years

▪️x+4=4(y+4)

▪️Hence we get two equations

▪️x=6y ......... (1)

▪️x+4=4(y+4) ..... (2)

▪️Simplifying eq (2)

▪️x+4=4y+16

▪️x−4y=12

▪️Put x=6y in eq (2), we get

▪️ 6y−4y=12

▪️2y=12

▪️ y=6 years

▪️and x=6y=36 years

▪️Present age of son =6 years

▪️and present age of father =36 years

Hopes it help you✌️✌️